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91B0: Is the target an ordinary object?
Returns with Z set if byte 0 of the target's record is 1: an object in one place. Doors and other things that exist in two places have 2.
Output
F Z set if the target is an ordinary object
91B0 LD IX,($B5F8) IX = the target's own record
91B4 LD A,(IX+$00) Does it occupy just one place (rather than two, like a door)?
91B7 DEC A
91B8 RET Z reflects the answer
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